Question

Three times m plus one equals 10 and 6n + 3 = 6 - n

Answer 1

Let's solve the equations one at a time.

1. **For the first equation:**
\[
3m + 1 = 10
\]

To solve for \( m \), we start by isolating \( m \):
\[
3m = 10 - 1
\]
\[
3m = 9
\]
\[
m = \frac{9}{3}
\]
\[
m = 3
\]

2. **For the second equation:**
\[
6n + 3 = 6 - n
\]

To solve for \( n \), we first add \( n \) to both sides:
\[
6n + n + 3 = 6
\]
\[
7n + 3 = 6
\]

Next, subtract 3 from both sides:
\[
7n = 6 - 3
\]
\[
7n = 3
\]
\[
n = \frac{3}{7}
\]

So, the solutions are:
\[
m = 3 \quad \text{and} \quad n = \frac{3}{7}
\]