What value falls in the solution set of the inequality −3(4k+1)<15 ?(1 point)

Responses

−4
negative 4

−5
negative 5

−32
Start Fraction negative 3 over 2 End Fraction

−1

1 answer

To solve the inequality \(-3(4k + 1) < 15\), we first distribute the \(-3\) on the left side:

\[ -3 \cdot 4k - 3 \cdot 1 < 15 \]

This gives us:

\[ -12k - 3 < 15 \]

Next, we add \(3\) to both sides to isolate the term with \(k\):

\[ -12k < 15 + 3 \] \[ -12k < 18 \]

Now, we divide both sides by \(-12\). Remember to flip the inequality sign when dividing by a negative number:

\[ k > \frac{18}{-12} \]

Simplifying \(\frac{18}{-12}\):

\[ k > -\frac{3}{2} \]

Now we can identify the values that fall in the solution set of \(k > -\frac{3}{2}\).

Among the provided options:

  • \(-4\) (is not greater than \(-\frac{3}{2}\))
  • \(-5\) (is not greater than \(-\frac{3}{2}\))
  • \(-32\) (is not greater than \(-\frac{3}{2}\))
  • \(-1\) (is greater than \(-\frac{3}{2}\))

Thus, the value that falls in the solution set of the inequality \(-3(4k+1)<15\) is:

\(-1\)