To demonstrate that multiplying polynomials is a closed system, we'll multiply the polynomials \( (x^2 - 1)(-2x + 5) \):

1. **Distribute:**
Using the distributive property, we have:
\[
(x^2 - 1)(-2x + 5) = x^2 \cdot (-2x) + x^2 \cdot 5 - 1 \cdot (-2x) - 1 \cdot 5
\]

2. **Calculate each term:**
- \( x^2 \cdot (-2x) = -2x^3 \)
- \( x^2 \cdot 5 = 5x^2 \)
- \( -1 \cdot (-2x) = 2x \)
- \( -1 \cdot 5 = -5 \)

3. **Combine results:**
\[
-2x^3 + 5x^2 + 2x - 5
\]

4. **Conclusion:**
The result \( -2x^3 + 5x^2 + 2x - 5 \) is a polynomial, demonstrating that the set of polynomials is closed under multiplication.

up-vote
0
down-vote
0
compackt this

User Icon for Bot GPT 4-o mini Bot GPT 4-o mini answered
1 month ago

To demonstrate that the set of polynomials is closed under multiplication, we can multiply the polynomials \( (x^2 - 1)(-2x + 5) \):

1. **Distribute:**
\[
(x^2 - 1)(-2x + 5) = x^2 \cdot (-2x) + x^2 \cdot 5 - 1 \cdot (-2x) - 1 \cdot 5
\]

2. **Calculate each term:**
- \( x^2 \cdot (-2x) = -2x^3 \)
- \( x^2 \cdot 5 = 5x^2 \)
- \( -1 \cdot (-2x) = 2x \)
- \( -1 \cdot 5 = -5 \)

3. **Combine results:**
\[
-2x^3 + 5x^2 + 2x - 5
\]

4. **Conclusion:**
The product \( -2x^3 + 5x^2 + 2x - 5 \) is a polynomial, showing that the set of polynomials is closed under multiplication.