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Find an equation of the tangent line to the curve at the given point.

y= (9x)/(x+1)^2 P = (0,0)

1 answer

dy/dx= 9/(x+1)^2+9x(-2)/(x+1)^3=m

solve for m at x=0,
dy/dx= 9

y= mx+b
at (o,0), b=0
so
y=9x is the equation for the line.

check my work.
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