Asked by candace
What mass in g of NaCl is formed from the reaction of 54.0 mL of a 0.078 M AgC2H3O2 solution with 71.0 mL of 0.109 M MgCl2 solution?
2 AgC2H3O2 (aq) + MgCl2 (aq) --> 2 AgCl (s) + Mg(C2H3O2)2 (aq)
2 AgC2H3O2 (aq) + MgCl2 (aq) --> 2 AgCl (s) + Mg(C2H3O2)2 (aq)
Answers
Answered by
DrBob222
You mean AgCl instead of NaCl.
Calculate moles AgC2H3O2. moles = M x L.
Do the same for MgCl2.
Look at how the moles combine and convert to moles AgCl. One of the reagent will be the limiting reagent unless you have stoichiometric amounts present. Then convert moles AgCl to grams. g = moles x molar mass.
Calculate moles AgC2H3O2. moles = M x L.
Do the same for MgCl2.
Look at how the moles combine and convert to moles AgCl. One of the reagent will be the limiting reagent unless you have stoichiometric amounts present. Then convert moles AgCl to grams. g = moles x molar mass.