To convert the binary number \(1011\) to its decimal equivalent, you can use the positional value of each bit:
\[ 1 \times 2^3 + 0 \times 2^2 + 1 \times 2^1 + 1 \times 2^0 \]
Calculating each term:
- \(1 \times 2^3 = 1 \times 8 = 8\)
- \(0 \times 2^2 = 0 \times 4 = 0\)
- \(1 \times 2^1 = 1 \times 2 = 2\)
- \(1 \times 2^0 = 1 \times 1 = 1\)
Now sum these values:
\[ 8 + 0 + 2 + 1 = 11 \]
Therefore, the decimal equivalent of the binary number \(1011\) is \(11\).