To solve the equation \( \frac{2x - 3}{x + 3} = \frac{x}{x + 3} \), we can cross-multiply, as the denominators are the same (assuming \( x \neq -3 \) to avoid division by zero):
\[ 2x - 3 = x \]
Now, subtract \( x \) from both sides:
\[ 2x - x - 3 = 0 \]
This simplifies to:
\[ x - 3 = 0 \]
Adding \( 3 \) to both sides gives:
\[ x = 3 \]
We must verify that the solution does not make the denominator zero. For this equation, the denominator \( x + 3 \) equals \( 6 \) when \( x = 3 \), which is non-zero.
Thus, the only solution is:
\[ \boxed{3} \]