Question
Consider the following expressions:
−6+3⋅5______16−−√+32÷8.
Which operator can be inserted to make the statement true?
(1 point)
Responses
>
greater than
=
equals
≤
less-than-or-equal-to
<
−6+3⋅5______16−−√+32÷8.
Which operator can be inserted to make the statement true?
(1 point)
Responses
>
greater than
=
equals
≤
less-than-or-equal-to
<
Answers
There are no human answers yet.
Answered by
GPT-4o mini
Let's evaluate the expressions on both sides of the inequality.
For the left side:
\[
-6 + 3 \cdot 5
\]
First, we perform the multiplication:
\[
3 \cdot 5 = 15
\]
Now we can add:
\[
-6 + 15 = 9
\]
Now for the right side:
\[
16 - \sqrt{16} + 32 \div 8
\]
First, we calculate \(\sqrt{16}\):
\[
\sqrt{16} = 4
\]
Next, we do the division:
\[
32 \div 8 = 4
\]
Now we can substitute these results back:
\[
16 - 4 + 4
\]
Now we perform the subtraction and addition:
\[
16 - 4 = 12
\]
\[
12 + 4 = 16
\]
Now we have the simplified expressions:
Left side: \(9\)
Right side: \(16\)
We need to compare \(9\) and \(16\). Since \(9 < 16\), we can use the less-than operator.
Thus, the correct operator to insert is:
< (less-than)
For the left side:
\[
-6 + 3 \cdot 5
\]
First, we perform the multiplication:
\[
3 \cdot 5 = 15
\]
Now we can add:
\[
-6 + 15 = 9
\]
Now for the right side:
\[
16 - \sqrt{16} + 32 \div 8
\]
First, we calculate \(\sqrt{16}\):
\[
\sqrt{16} = 4
\]
Next, we do the division:
\[
32 \div 8 = 4
\]
Now we can substitute these results back:
\[
16 - 4 + 4
\]
Now we perform the subtraction and addition:
\[
16 - 4 = 12
\]
\[
12 + 4 = 16
\]
Now we have the simplified expressions:
Left side: \(9\)
Right side: \(16\)
We need to compare \(9\) and \(16\). Since \(9 < 16\), we can use the less-than operator.
Thus, the correct operator to insert is:
< (less-than)
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