Question

Drag and drop Solve the following:(2 points)
ax+15=44 (Response Area)

ax−44<15 (Response Area)

OPTIONS FOR THE "RESPONSE AREAS" X < 59/a, X = 59/a, x < 59a, x = 29a, x < 29/a, x = 59a, x < 29a, x = 29/a

Answer 1

To solve the given equations and inequalities, let's start with them one by one.

1. **Equation**: \( ax + 15 = 44 \)

To solve for \( x \):
\[
ax = 44 - 15
\]
\[
ax = 29
\]
\[
x = \frac{29}{a}
\]
So the solution for the equation is \( x = \frac{29}{a} \).

2. **Inequality**: \( ax - 44 < 15 \)

To solve for \( x \):
\[
ax < 15 + 44
\]
\[
ax < 59
\]
Dividing both sides by \( a \) (assuming \( a > 0 \)):
\[
x < \frac{59}{a}
\]
If \( a < 0 \), the inequality would flip:
\[
x > \frac{59}{a}
\]

For the provided options, assuming \( a > 0 \), we have:
- From the equation: \( x = \frac{29}{a} \)
- From the inequality: \( x < \frac{59}{a} \)

Thus, the appropriate assignments to the response areas would be:
- **Equation**: \( x = \frac{29}{a} \)
- **Inequality**: \( x < \frac{59}{a} \)

You can drag and drop these solutions into the corresponding response areas.