Question

solve th round to the nearest tent
6m-2m=28

solve then round to the nearest tenth
3(p−5)+4p=p+9

Answer 1

Let's solve each equation step by step.

**1. Solve the equation \(6m - 2m = 28\):**

Combine like terms:
\[
6m - 2m = 4m
\]
So the equation simplifies to:
\[
4m = 28
\]

Now, divide both sides by 4:
\[
m = \frac{28}{4} = 7
\]

Since the result is already an integer, rounding to the nearest tenth gives:
\[
m = 7.0
\]

**2. Solve the equation \(3(p−5) + 4p = p + 9\):**

First, distribute \(3\) in the left term:
\[
3p - 15 + 4p = p + 9
\]

Combine like terms:
\[
(3p + 4p) - 15 = p + 9 \implies 7p - 15 = p + 9
\]

Now, isolate \(p\) by moving \(p\) to the left side:
\[
7p - p - 15 = 9
\]
This simplifies to:
\[
6p - 15 = 9
\]

Next, add 15 to both sides:
\[
6p = 9 + 15
\]
\[
6p = 24
\]

Now, divide both sides by 6:
\[
p = \frac{24}{6} = 4
\]

Again, since the result is an integer, rounding to the nearest tenth gives:
\[
p = 4.0
\]

**Final Results:**
- \(m = 7.0\)
- \(p = 4.0\)