solve th round to the nearest tent

6m-2m=28

solve then round to the nearest tenth
3(p−5)+4p=p+9

1 answer

Let's solve each equation step by step.

1. Solve the equation \(6m - 2m = 28\):

Combine like terms: \[ 6m - 2m = 4m \] So the equation simplifies to: \[ 4m = 28 \]

Now, divide both sides by 4: \[ m = \frac{28}{4} = 7 \]

Since the result is already an integer, rounding to the nearest tenth gives: \[ m = 7.0 \]

2. Solve the equation \(3(p−5) + 4p = p + 9\):

First, distribute \(3\) in the left term: \[ 3p - 15 + 4p = p + 9 \]

Combine like terms: \[ (3p + 4p) - 15 = p + 9 \implies 7p - 15 = p + 9 \]

Now, isolate \(p\) by moving \(p\) to the left side: \[ 7p - p - 15 = 9 \] This simplifies to: \[ 6p - 15 = 9 \]

Next, add 15 to both sides: \[ 6p = 9 + 15 \] \[ 6p = 24 \]

Now, divide both sides by 6: \[ p = \frac{24}{6} = 4 \]

Again, since the result is an integer, rounding to the nearest tenth gives: \[ p = 4.0 \]

Final Results:

  • \(m = 7.0\)
  • \(p = 4.0\)