Question

question 1 a)what is the solution set of x+2≥6 and 3x≥6?(1 point) {x|x$$} question 2 a)what is the solution set of 2x−3=5 and 5x+3>−12 ?(1 point) {$$}

Answer 1

Q1 IS WRONG

Answer 2

Q1 is = What is the solution set of x + 2 greater than or equal two 6 and 3x is greater than or equal to 6

Answer 3

Its not four give me a diferent answer

Answer 4

what does geq 4 mean?

Answer 5

Let's solve each question step by step.

### Question 1:
We need to solve the inequalities \( x + 2 \geq 6 \) and \( 3x \geq 6 \).

1. **Solve \( x + 2 \geq 6 \):**
\[
x + 2 \geq 6 \\
x \geq 6 - 2 \\
x \geq 4
\]

2. **Solve \( 3x \geq 6 \):**
\[
3x \geq 6 \\
x \geq \frac{6}{3} \\
x \geq 2
\]

Now we need to find the intersection of the two solution sets:
- From \( x + 2 \geq 6 \), we have \( x \geq 4 \).
- From \( 3x \geq 6 \), we have \( x \geq 2 \).

The more restrictive condition is \( x \geq 4 \).

**Solution set:**
\[
\{x | x \geq 4\}
\]

### Question 2:
We need to solve the equation \( 2x - 3 = 5 \) and the inequality \( 5x + 3 > -12 \).

1. **Solve \( 2x - 3 = 5 \):**
\[
2x - 3 = 5 \\
2x = 5 + 3 \\
2x = 8 \\
x = \frac{8}{2} \\
x = 4
\]

2. **Solve \( 5x + 3 > -12 \):**
\[
5x + 3 > -12 \\
5x > -12 - 3 \\
5x > -15 \\
x > \frac{-15}{5} \\
x > -3
\]

Now, we have:
- The solution from \( 2x - 3 = 5 \) gives \( x = 4 \).
- The solution from \( 5x + 3 > -12 \) gives \( x > -3 \).

Since we are looking for the solution that meets both conditions, we have:
- \( x = 4 \) satisfies \( x > -3 \).

**Solution set:**
\[
\{x | x = 4\}
\]

### Final Answers:
1. Question 1: \(\{x | x \geq 4\}\)
2. Question 2: \(\{x | x = 4\}\)

Answer 6

Let's carefully reevaluate Question 1 and solve the inequalities step by step again.

### Question 1:
We need to solve the inequalities \( x + 2 \geq 6 \) and \( 3x \geq 6 \).

1. **Solve \( x + 2 \geq 6 \):**
\[
x + 2 \geq 6 \\
x \geq 6 - 2 \\
x \geq 4
\]

2. **Solve \( 3x \geq 6 \):**
\[
3x \geq 6 \\
x \geq \frac{6}{3} \\
x \geq 2
\]

Next, we need the combined solution for the inequalities. We have:
- From \( x + 2 \geq 6 \), we have \( x \geq 4 \).
- From \( 3x \geq 6 \), we have \( x \geq 2 \).

### Combining the Solutions:
The inequality \( x \geq 4 \) is more restrictive than \( x \geq 2 \). Therefore, the overall solution set is determined by the more stringent inequality.

**Final Solution Set:**
\[
\{ x | x \geq 4 \}
\]

Since the solution holds true, if there's something specific that you believe is wrong, please clarify what aspect you find incorrect!

Answer 7

Thank you for your clarification! Let's solve the inequalities correctly based on your phrasing:

1. \( x + 2 \geq 6 \)
2. \( 3x \geq 6 \)

We'll solve each inequality separately and then find the solution set that satisfies both.

### Step 1: Solve \( x + 2 \geq 6 \)
\[
x + 2 \geq 6
\]
Subtract 2 from both sides:
\[
x \geq 6 - 2
\]
\[
x \geq 4
\]

### Step 2: Solve \( 3x \geq 6 \)
\[
3x \geq 6
\]
Divide both sides by 3:
\[
x \geq \frac{6}{3}
\]
\[
x \geq 2
\]

### Conclusion: Combine the Solutions
From the two inequalities, we find:
- From \( x + 2 \geq 6 \): \( x \geq 4 \)
- From \( 3x \geq 6 \): \( x \geq 2 \)

The solution set that satisfies both inequalities is determined by the more restrictive condition. In this case, \( x \geq 4 \) is more restrictive than \( x \geq 2 \).

### Final Solution Set:
\[
\{ x | x \geq 4 \}
\]

If you intended for something different in your question, please let me know!

Answer 8

Let’s carefully re-evaluate and clarify the solution step by step again, ensuring there are no mistakes.

### Given Inequalities:
1. \( x + 2 \geq 6 \)
2. \( 3x \geq 6 \)

### Step 1: Solve \( x + 2 \geq 6 \)
Subtract 2 from both sides:
\[
x \geq 6 - 2
\]
\[
x \geq 4
\]

### Step 2: Solve \( 3x \geq 6 \)
Divide both sides by 3:
\[
x \geq \frac{6}{3}
\]
\[
x \geq 2
\]

### Conclusion: Combine the Solutions
The two inequalities yield:
1. From \( x + 2 \geq 6 \): \( x \geq 4 \)
2. From \( 3x \geq 6 \): \( x \geq 2 \)

Now, if we look at the solutions together:
- The first inequality tells us \( x \) must be at least 4.
- The second inequality tells us \( x \) must be at least 2.

The **intersection** of both inequalities is determined by the more restrictive condition, which is \( x \geq 4 \). Therefore, this means every solution that satisfies both conditions must be at least 4.

### Final Solution Set:
\[
\{ x | x \geq 4 \}
\]

If there's a misunderstanding or if you are seeking a specific kind of response (such as a different interpretation of the inequalities), please provide further details! I am here to help.

Answer 9

The notation \( \geq \) stands for "greater than or equal to." Therefore, when we write \( x \geq 4 \), it means that \( x \) can take any value that is either:

- Greater than 4 (e.g., 5, 6, 7, etc.)
- Equal to 4 (i.e., \( x = 4 \))

In set notation, the solution \( \{ x | x \geq 4 \} \) represents all numbers \( x \) such that \( x \) is greater than or equal to 4. It includes 4 itself and all numbers that follow it on the number line.

If there's something else you'd like to understand or if you have additional questions, feel free to ask!