Let's solve each question step by step.
Question 1:
We need to solve the inequalities \( x + 2 \geq 6 \) and \( 3x \geq 6 \).
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Solve \( x + 2 \geq 6 \): \[ x + 2 \geq 6 \ x \geq 6 - 2 \ x \geq 4 \]
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Solve \( 3x \geq 6 \): \[ 3x \geq 6 \ x \geq \frac{6}{3} \ x \geq 2 \]
Now we need to find the intersection of the two solution sets:
- From \( x + 2 \geq 6 \), we have \( x \geq 4 \).
- From \( 3x \geq 6 \), we have \( x \geq 2 \).
The more restrictive condition is \( x \geq 4 \).
Solution set: \[ {x | x \geq 4} \]
Question 2:
We need to solve the equation \( 2x - 3 = 5 \) and the inequality \( 5x + 3 > -12 \).
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Solve \( 2x - 3 = 5 \): \[ 2x - 3 = 5 \ 2x = 5 + 3 \ 2x = 8 \ x = \frac{8}{2} \ x = 4 \]
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Solve \( 5x + 3 > -12 \): \[ 5x + 3 > -12 \ 5x > -12 - 3 \ 5x > -15 \ x > \frac{-15}{5} \ x > -3 \]
Now, we have:
- The solution from \( 2x - 3 = 5 \) gives \( x = 4 \).
- The solution from \( 5x + 3 > -12 \) gives \( x > -3 \).
Since we are looking for the solution that meets both conditions, we have:
- \( x = 4 \) satisfies \( x > -3 \).
Solution set: \[ {x | x = 4} \]
Final Answers:
- Question 1: \({x | x \geq 4}\)
- Question 2: \({x | x = 4}\)