To simplify the expression \((13−7)^0 \cdot 7^{-11}7^{-9}\), we can follow the properties of exponents.
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Evaluate \((13-7)^0\): Any non-zero expression raised to the power of 0 is 1. Therefore, \((13−7)^0 = 1\).
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Combine the exponents for \(7^{-11} \cdot 7^{-9}\): When multiplying expressions with the same base, we add the exponents: \[ 7^{-11} \cdot 7^{-9} = 7^{-11 + (-9)} = 7^{-20} \]
Now, combining everything together, we have: \[ (13−7)^0 \cdot 7^{-11} \cdot 7^{-9} = 1 \cdot 7^{-20} = 7^{-20} \]
Since \(7^{-20}\) can also be expressed as \(\frac{1}{7^{20}}\), we can see if any of the options match that.
Now looking at your choices:
- \(13^{-7} \cdot 7^2\)
- \(\frac{1}{49}\) - this is \(\frac{1}{7^2}\), not our answer.
- \(13 \cdot 79711\) - doesn't match.
- \(71179\) - doesn’t correspond to our simplified form.
None of the choices seem to match with \(7^{-20}\) or \(\frac{1}{7^{20}}\). Please check the options again for any that represent \(7^{-20}\) or \(\frac{1}{7^{20}}\).
If there are any more options or information, feel free to provide it!