Asked by capybara for life
Step 1: Simplify the Numerator
First, let's focus on the top part, which is called the numerator:
\[
3x^2 + 2x - 5x - 2x^2 + 2
\]
We can combine like terms here. Group the \(x^2\) terms together and the \(x\) terms together:
\[
(3x^2 - 2x^2) + (2x - 5x) + 2
\]
Now, let's do the calculations:
- For \(3x^2 - 2x^2\), we get \(x^2\).
- For \(2x - 5x\), we get \(-3x\).
Putting it all together, we have:
\[
x^2 - 3x + 2
\]
### Step 2: Factor the Numerator
Next, we need to factor \(x^2 - 3x + 2\). We are looking for two numbers that multiply to \(2\) (the last number) and add up to \(-3\) (the middle number). Those numbers are \(-1\) and \(-2\). So, we can write:
\[
x^2 - 3x + 2 = (x - 1)(x - 2)
\]
### Step 3: Simplify the Denominator
Now, let's look at the bottom part, or the denominator:
\[
(x - 2)(x - 1)(x + 2)(x - 2)(x + 1)(x + 2)
\]
Notice we can group the factors:
- We have two \( (x - 2) \) factors: \( (x - 2)(x - 2) = (x - 2)^2 \)
- We have two \( (x + 2) \) factors: \( (x + 2)(x + 2) = (x + 2)^2 \)
So, the denominator can be rewritten as:
\[
(x - 2)^2 (x - 1)(x + 2)^2 (x + 1)
\]
### Step 4: Rewrite the Whole Expression
Now we can rewrite the whole expression using what we found:
\[
\frac{(x - 1)(x - 2)}{(x - 2)^2 (x - 1)(x + 2)^2 (x + 1)}
\]
### Step 5: Cancel Out Common Factors
In this fraction, we can cancel out what’s the same on the top and bottom:
1. The \( (x - 1) \) in the numerator and denominator cancels.
2. One \( (x - 2) \) in the numerator cancels with one \( (x - 2) \) in the denominator.
After canceling, we are left with:
\[
\frac{1}{(x - 2)(x + 2)^2(x + 1)}
\]
### Final Answer
So, the final answer to our original expression is:
\[
\boxed{\frac{1}{(x - 2)(x + 2)^2(x + 1)}}
\]
make this smaller
First, let's focus on the top part, which is called the numerator:
\[
3x^2 + 2x - 5x - 2x^2 + 2
\]
We can combine like terms here. Group the \(x^2\) terms together and the \(x\) terms together:
\[
(3x^2 - 2x^2) + (2x - 5x) + 2
\]
Now, let's do the calculations:
- For \(3x^2 - 2x^2\), we get \(x^2\).
- For \(2x - 5x\), we get \(-3x\).
Putting it all together, we have:
\[
x^2 - 3x + 2
\]
### Step 2: Factor the Numerator
Next, we need to factor \(x^2 - 3x + 2\). We are looking for two numbers that multiply to \(2\) (the last number) and add up to \(-3\) (the middle number). Those numbers are \(-1\) and \(-2\). So, we can write:
\[
x^2 - 3x + 2 = (x - 1)(x - 2)
\]
### Step 3: Simplify the Denominator
Now, let's look at the bottom part, or the denominator:
\[
(x - 2)(x - 1)(x + 2)(x - 2)(x + 1)(x + 2)
\]
Notice we can group the factors:
- We have two \( (x - 2) \) factors: \( (x - 2)(x - 2) = (x - 2)^2 \)
- We have two \( (x + 2) \) factors: \( (x + 2)(x + 2) = (x + 2)^2 \)
So, the denominator can be rewritten as:
\[
(x - 2)^2 (x - 1)(x + 2)^2 (x + 1)
\]
### Step 4: Rewrite the Whole Expression
Now we can rewrite the whole expression using what we found:
\[
\frac{(x - 1)(x - 2)}{(x - 2)^2 (x - 1)(x + 2)^2 (x + 1)}
\]
### Step 5: Cancel Out Common Factors
In this fraction, we can cancel out what’s the same on the top and bottom:
1. The \( (x - 1) \) in the numerator and denominator cancels.
2. One \( (x - 2) \) in the numerator cancels with one \( (x - 2) \) in the denominator.
After canceling, we are left with:
\[
\frac{1}{(x - 2)(x + 2)^2(x + 1)}
\]
### Final Answer
So, the final answer to our original expression is:
\[
\boxed{\frac{1}{(x - 2)(x + 2)^2(x + 1)}}
\]
make this smaller
Answers
Answered by
GPT-4o mini
Certainly! Let’s streamline the explanation of the simplification process for the expression step-by-step:
### Given Expression
Start with the expression:
\[
\frac{3x^2 + 2x - 5x - 2x^2 + 2}{(x - 2)(x - 1)(x + 2)(x - 2)(x + 1)(x + 2)}
\]
### Step 1: Simplify the Numerator
Combine like terms in the numerator:
\[
3x^2 - 2x^2 + 2x - 5x + 2 = (3x^2 - 2x^2) + (2x - 5x) + 2 = x^2 - 3x + 2
\]
### Step 2: Factor the Numerator
Factor \(x^2 - 3x + 2\) to get:
\[
x^2 - 3x + 2 = (x - 1)(x - 2)
\]
### Step 3: Simplify the Denominator
The denominator is:
\[
(x - 2)(x - 1)(x + 2)(x - 2)(x + 1)(x + 2)
\]
Group factors:
\[
(x - 2)^2 (x - 1)(x + 2)^2 (x + 1)
\]
### Step 4: Rewrite the Whole Expression
Now the fraction is:
\[
\frac{(x - 1)(x - 2)}{(x - 2)^2 (x - 1)(x + 2)^2 (x + 1)}
\]
### Step 5: Cancel Out Common Factors
Cancel \( (x - 1) \) and one \( (x - 2) \):
\[
\frac{1}{(x - 2)(x + 2)^2(x + 1)}
\]
### Final Answer
The final simplified expression is:
\[
\boxed{\frac{1}{(x - 2)(x + 2)^2(x + 1)}}
\]
### Given Expression
Start with the expression:
\[
\frac{3x^2 + 2x - 5x - 2x^2 + 2}{(x - 2)(x - 1)(x + 2)(x - 2)(x + 1)(x + 2)}
\]
### Step 1: Simplify the Numerator
Combine like terms in the numerator:
\[
3x^2 - 2x^2 + 2x - 5x + 2 = (3x^2 - 2x^2) + (2x - 5x) + 2 = x^2 - 3x + 2
\]
### Step 2: Factor the Numerator
Factor \(x^2 - 3x + 2\) to get:
\[
x^2 - 3x + 2 = (x - 1)(x - 2)
\]
### Step 3: Simplify the Denominator
The denominator is:
\[
(x - 2)(x - 1)(x + 2)(x - 2)(x + 1)(x + 2)
\]
Group factors:
\[
(x - 2)^2 (x - 1)(x + 2)^2 (x + 1)
\]
### Step 4: Rewrite the Whole Expression
Now the fraction is:
\[
\frac{(x - 1)(x - 2)}{(x - 2)^2 (x - 1)(x + 2)^2 (x + 1)}
\]
### Step 5: Cancel Out Common Factors
Cancel \( (x - 1) \) and one \( (x - 2) \):
\[
\frac{1}{(x - 2)(x + 2)^2(x + 1)}
\]
### Final Answer
The final simplified expression is:
\[
\boxed{\frac{1}{(x - 2)(x + 2)^2(x + 1)}}
\]