Asked by capybara for life
Find the expression that is equivalent to 3𝑥2+2𝑥−5𝑥−2𝑥2+2 (𝑥−2)(𝑥−1) (𝑥+2)(𝑥−2) (𝑥+1)(𝑥+2)
Answers
Answered by
GPT-4o mini
To simplify the given expression \( \frac{3x^2 + 2x - 5x - 2x^2 + 2}{(x - 2)(x - 1)(x + 2)(x - 2)(x + 1)(x + 2)} \), we first need to simplify the numerator and the denominator.
### Step 1: Simplify the Numerator
Start with the expression in the numerator:
\[
3x^2 + 2x - 5x - 2x^2 + 2
\]
Combine like terms:
\[
(3x^2 - 2x^2) + (2x - 5x) + 2
\]
This results in:
\[
x^2 - 3x + 2
\]
### Step 2: Factor the Numerator
Now, we will factor \( x^2 - 3x + 2 \):
\[
x^2 - 3x + 2 = (x - 1)(x - 2)
\]
### Step 3: Simplify the Denominator
Now, let's look at the denominator:
\[
(x - 2)(x - 1)(x + 2)(x - 2)(x + 1)(x + 2) = (x - 2)^2(x - 1)(x + 2)^2(x + 1)
\]
### Step 4: Rewrite the Complete Expression
Now substituting in the factored numerator gives:
\[
\frac{(x - 1)(x - 2)}{(x - 2)^2(x - 1)(x + 2)^2(x + 1)}
\]
### Step 5: Cancel Common Factors
In this expression, we can cancel out \( (x - 1) \) and one \( (x - 2) \):
\[
\frac{\cancel{(x - 1)} (x - 2)}{(x - 2) \cancel{(x - 1)} (x + 2)^2 (x + 1)} = \frac{1}{(x - 2)(x + 2)^2(x + 1)}
\]
### Final Result:
Thus, the expression that is equivalent to the given one is:
\[
\boxed{\frac{1}{(x - 2)(x + 2)^2(x + 1)}}
\]
### Step 1: Simplify the Numerator
Start with the expression in the numerator:
\[
3x^2 + 2x - 5x - 2x^2 + 2
\]
Combine like terms:
\[
(3x^2 - 2x^2) + (2x - 5x) + 2
\]
This results in:
\[
x^2 - 3x + 2
\]
### Step 2: Factor the Numerator
Now, we will factor \( x^2 - 3x + 2 \):
\[
x^2 - 3x + 2 = (x - 1)(x - 2)
\]
### Step 3: Simplify the Denominator
Now, let's look at the denominator:
\[
(x - 2)(x - 1)(x + 2)(x - 2)(x + 1)(x + 2) = (x - 2)^2(x - 1)(x + 2)^2(x + 1)
\]
### Step 4: Rewrite the Complete Expression
Now substituting in the factored numerator gives:
\[
\frac{(x - 1)(x - 2)}{(x - 2)^2(x - 1)(x + 2)^2(x + 1)}
\]
### Step 5: Cancel Common Factors
In this expression, we can cancel out \( (x - 1) \) and one \( (x - 2) \):
\[
\frac{\cancel{(x - 1)} (x - 2)}{(x - 2) \cancel{(x - 1)} (x + 2)^2 (x + 1)} = \frac{1}{(x - 2)(x + 2)^2(x + 1)}
\]
### Final Result:
Thus, the expression that is equivalent to the given one is:
\[
\boxed{\frac{1}{(x - 2)(x + 2)^2(x + 1)}}
\]
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