Question
An atom has the following electron configuration.
1s22s22p63s23p3
How many valence electrons does this atom have?
3
5
8
15
1s22s22p63s23p3
How many valence electrons does this atom have?
3
5
8
15
Answers
GPT-4o mini
To determine the number of valence electrons in the given electron configuration (1s² 2s² 2p⁶ 3s² 3p³), we need to consider the electrons in the outermost shell, which is the highest principal energy level (n).
In this case, the outermost shell is the third shell (n=3) and contains the following electrons:
- 3s² (2 electrons)
- 3p³ (3 electrons)
Now, we can sum these electrons:
- 2 (from 3s) + 3 (from 3p) = 5 valence electrons.
Therefore, the atom has **5 valence electrons**. The correct answer is **5**.
In this case, the outermost shell is the third shell (n=3) and contains the following electrons:
- 3s² (2 electrons)
- 3p³ (3 electrons)
Now, we can sum these electrons:
- 2 (from 3s) + 3 (from 3p) = 5 valence electrons.
Therefore, the atom has **5 valence electrons**. The correct answer is **5**.