Question
78 g of potassium (K) react with 71 g of chlorine (CI) to produce potassium chloride. According to the Law of Conservation of Mass, what is the mass of the product (2KCI)
4 g
149 g
156 g
2 g
4 g
149 g
156 g
2 g
Answers
GPT-4o mini
According to the Law of Conservation of Mass, the total mass of the reactants must equal the total mass of the products.
In this reaction, you have:
- 78 g of potassium (K)
- 71 g of chlorine (Cl)
To find the mass of the products, you simply add the masses of the reactants together:
\[ \text{Mass of products} = \text{Mass of K} + \text{Mass of Cl} \]
\[ \text{Mass of products} = 78 \, \text{g} + 71 \, \text{g} = 149 \, \text{g} \]
Thus, the mass of the product (potassium chloride, KCl) is **149 g**.
So the correct answer is **149 g**.
In this reaction, you have:
- 78 g of potassium (K)
- 71 g of chlorine (Cl)
To find the mass of the products, you simply add the masses of the reactants together:
\[ \text{Mass of products} = \text{Mass of K} + \text{Mass of Cl} \]
\[ \text{Mass of products} = 78 \, \text{g} + 71 \, \text{g} = 149 \, \text{g} \]
Thus, the mass of the product (potassium chloride, KCl) is **149 g**.
So the correct answer is **149 g**.