To find the coordinates of \( C' \) after Jarvis translates rectangle \( ABCD \) horizontally by \(-4\) and vertically by \(+3\), we need to first identify the coordinates of point \( C \).
Assuming you have the coordinates of point \( C \) as \((x_C, y_C)\), the translation will adjust the coordinates as follows:
- Horizontal translation of \(-4\): This will subtract \(4\) from the x-coordinate.
- Vertical translation of \(+3\): This will add \(3\) to the y-coordinate.
So, the new coordinates of point \( C' \) after translation will be:
\[ C' = (x_C - 4, y_C + 3) \]
To give a specific answer, please provide the coordinates of point \( C \) from the image.