It takes 1 molecule of nitrogen and 3

Question

molecules of hydrogen to produce 2
molecules of ammonia using the following formula:

1N2+ 3H2 → 2NH3

Identify which combination of molecules will produce ammonia with no leftovers?

(1 point)
Responses

4N2 and 4H2
4 n sub 2 and 4 h sub 2

2N2 and 6H2
2 n sub 2 and 6 h sub 2

8N2 and 4H2
8 n sub 2 and 4 h sub 2

5N2 and 6H2

Answer 1

To determine which combination of molecules will produce ammonia with no leftovers, we need to look at the stoichiometry of the reaction:

\[ \text{N}_2 + 3\text{H}_2 \rightarrow 2\text{NH}_3 \]

From the equation, we see that:

• 1 molecule of nitrogen (\(N_2\)) reacts with 3 molecules of hydrogen (\(H_2\)) to produce 2 molecules of ammonia (\(NH_3\)).

This means that for every 1 mole of \(N_2\), we need 3 moles of \(H_2\).

Now, let's analyze the options given.

1. 4N2 and 4H2:

   • For 4 molecules of \(N_2\):
     • Required \(H_2 = 4 \times 3 = 12\)
     • We have 4 \(H_2\) → not enough.

2. 2N2 and 6H2:

   • For 2 molecules of \(N_2\):
     • Required \(H_2 = 2 \times 3 = 6\)
     • We have 6 \(H_2\) → just enough.

3. 8N2 and 4H2:

   • For 8 molecules of \(N_2\):
     • Required \(H_2 = 8 \times 3 = 24\)
     • We have 4 \(H_2\) → not enough.

4. 5N2 and 6H2:

   • For 5 molecules of \(N_2\):
     • Required \(H_2 = 5 \times 3 = 15\)
     • We have 6 \(H_2\) → not enough.

Based on this analysis, the correct option that produces ammonia with no leftovers is:

2N2 and 6H2.