Question

(9x^2-6x+2) - (x^2+4x-39)
the difference between polynomials is?

Answer 1

theres only supposed to be one sum

Answer 2

To find the difference between the polynomials \((9x^2 - 6x + 2)\) and \((x^2 + 4x - 39)\), we can subtract the second polynomial from the first:

\[
(9x^2 - 6x + 2) - (x^2 + 4x - 39)
\]

Distributing the negative sign across the second polynomial, we get:

\[
9x^2 - 6x + 2 - x^2 - 4x + 39
\]

Now, we can combine like terms:

1. Combine \(9x^2\) and \(-x^2\):
\[
9x^2 - x^2 = 8x^2
\]

2. Combine \(-6x\) and \(-4x\):
\[
-6x - 4x = -10x
\]

3. Combine \(2\) and \(39\):
\[
2 + 39 = 41
\]

Putting it all together, the result is:

\[
8x^2 - 10x + 41
\]

Thus, the difference between the polynomials is:

\[
\boxed{8x^2 - 10x + 41}
\]

Answer 3

Apologies for any confusion! Let's clarify the subtraction of the two polynomials step by step and focus on combining the terms correctly:

We start with:

\[
(9x^2 - 6x + 2) - (x^2 + 4x - 39)
\]

Distributing the negative:

\[
9x^2 - 6x + 2 - x^2 - 4x + 39
\]

Now, combining like terms:

1. **For \(x^2\) terms:**
\[
9x^2 - x^2 = 8x^2
\]

2. **For \(x\) terms:**
\[
-6x - 4x = -10x
\]

3. **For constant terms:**
\[
2 + 39 = 41
\]

So, combining everything, we have:

\[
8x^2 - 10x + 41
\]

The result is indeed a single polynomial expression, which is:

\[
\boxed{8x^2 - 10x + 41}
\]

I hope this clarifies the answer! If you need further assistance or additional information, feel free to ask.