To graph the linear equation \( y = 23x - 1 \), we can analyze its slope and y-intercept.
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Y-intercept: The y-intercept occurs when \( x = 0 \). Plugging in \( x = 0 \): \[ y = 23(0) - 1 = -1 \] So the point (0, -1) is on the graph.
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Slope: The slope is 23, which means that for every 1 unit increase in \( x \), \( y \) increases by 23 units.
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Finding another point: Using the y-intercept (0, -1), we can find another point by increasing \( x \) by 1: \[ x = 1 \quad \Rightarrow \quad y = 23(1) - 1 = 22 \] Thus, the point (1, 22) is also on the graph.
Now, we can plot these points on a coordinate plane and draw a line through them, extending the line in both directions.
From your description, the appropriate choice that resembles this graph should have the points \((0, -1)\) and \((3, 1)\) because they are the only one that fits the model where as you increment x by a certain amount, y increases significantly due to the slope of 23.
Thus, the linear equation \( y = 23x - 1 \) is correctly represented by the graph that includes the points:
- (0, -1)
- (1, 22)
None of the points in the provided descriptions seem to accurately represent this line based on the steep slope of 23. Therefore, based on the information provided, the accurate understanding of the graph for the equation \( y=23x−1 \) may not be represented correctly in the options you've shared.