To graph the linear equation \( y = -3x + 2 \), we need to find points that satisfy the equation.
Let's check the points given in the options:
1. Check (1, -1): \[ y = -3(1) + 2 = -3 + 2 = -1 \quad \text{(Valid)} \]
2. Check (0, 2): \[ y = -3(0) + 2 = 0 + 2 = 2 \quad \text{(Valid)} \]
So, option A gives us the points \( (1, -1) \) and \( (0, 2) \).
Now let's check the other options:
B. Check (1, 5): \[ y = -3(1) + 2 = -3 + 2 = -1 \quad \text{(Not valid)} \]
C. Check (1, -5): \[ y = -3(1) + 2 = -3 + 2 = -1 \quad \text{(Not valid)} \]
D. Check (-2, 2): \[ y = -3(-2) + 2 = 6 + 2 = 8 \quad \text{(Not valid)} \]
So, based on the checks, the only valid points from option A are (1, -1) and (0, 2).
Therefore, the correct answer is:
A. (1, -1), (0, 2)