Question

Graph the linear equation y = -3x + 2.
A. (1, -1), (0, 2)
B. (1, 5), (0, 3)
C. (1, -5), (0, -2)
D. (-2, 2), (0, 1)

Answer 1

To graph the linear equation \( y = -3x + 2 \), we need to find points that satisfy the equation.

Let's check the points given in the options:

**1. Check (1, -1):**
\[
y = -3(1) + 2 = -3 + 2 = -1 \quad \text{(Valid)}
\]

**2. Check (0, 2):**
\[
y = -3(0) + 2 = 0 + 2 = 2 \quad \text{(Valid)}
\]

So, option A gives us the points \( (1, -1) \) and \( (0, 2) \).

Now let's check the other options:

**B. Check (1, 5):**
\[
y = -3(1) + 2 = -3 + 2 = -1 \quad \text{(Not valid)}
\]

**C. Check (1, -5):**
\[
y = -3(1) + 2 = -3 + 2 = -1 \quad \text{(Not valid)}
\]

**D. Check (-2, 2):**
\[
y = -3(-2) + 2 = 6 + 2 = 8 \quad \text{(Not valid)}
\]

So, based on the checks, the only valid points from option A are **(1, -1)** and **(0, 2)**.

Therefore, the correct answer is:

**A. (1, -1), (0, 2)**