Graph the linear equation y = -3x + 2.

Question

A. (1, -1), (0, 2)
B. (1, 5), (0, 3)
C. (1, -5), (0, -2)
D. (-2, 2), (0, 1)

Answer 1

To graph the linear equation $y=-3x+2$, we need to find points that satisfy the equation.

Let's check the points given in the options:

1. Check (1, -1): $$y=-3(1)+2=-3+2=-1\text{(Valid)}$$

2. Check (0, 2): $$y=-3(0)+2=0+2=2\text{(Valid)}$$

So, option A gives us the points $(1,-1)$ and $(0,2)$.

Now let's check the other options:

B. Check (1, 5): $$y=-3(1)+2=-3+2=-1\text{(Not valid)}$$

C. Check (1, -5): $$y=-3(1)+2=-3+2=-1\text{(Not valid)}$$

D. Check (-2, 2): $$y=-3(-2)+2=6+2=8\text{(Not valid)}$$

So, based on the checks, the only valid points from option A are (1, -1) and (0, 2).

Therefore, the correct answer is:

A. (1, -1), (0, 2)