Use the image to answer the question.

To determine which option is cheaper per day, we can evaluate the cost of each option for different numbers of rides (x) using the equations provided.

Option A: \( y = 4.25x \)

Now, let's calculate the cost for Option A for several values of x (number of rides):

- For \( x = 0 \): \( y = 4.25(0) = 0 \)
- For \( x = 5 \): \( y = 4.25(5) = 21.25 \)
- For \( x = 10 \): \( y = 4.25(10) = 42.50 \)
- For \( x = 15 \): \( y = 4.25(15) = 63.75 \)

Now, let's summarize the costs for Option B from the graph:

- For \( x = 0 \): Cost = 0
- For \( x = 5 \): Cost = 20
- For \( x = 10 \): Cost = 40
- For \( x = 15 \): Cost = 60

Now, we can compare the costs for Option A and Option B:

| Rides (x) | Option A Cost | Option B Cost |
|-----------|----------------|----------------|
| 0 | $0 | $0 |
| 5 | $21.25 | $20 |
| 10 | $42.50 | $40 |
| 15 | $63.75 | $60 |

From the table, we can see:

- For 5 rides, Option B ($20) is cheaper than Option A ($21.25).
- For 10 rides, Option B ($40) is cheaper than Option A ($42.50).
- For 15 rides, Option B ($60) is cheaper than Option A ($63.75).

Therefore, Option B is cheaper per day for all ride counts (except for 0 rides, where both options cost nothing).

So, the answer is:

**2** is cheaper per day.