To determine which two equations have the same solution, we will solve each equation step by step:
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Equation: \(2(5x+4)=8x+28\)
Simplifying: \[ 10x + 8 = 8x + 28 \] Subtract \(8x\) from both sides: \[ 2x + 8 = 28 \] Subtract \(8\) from both sides: \[ 2x = 20 \] Divide by \(2\): \[ x = 10 \]
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Equation: \(\frac{x}{2}+4=5x-10\)
Simplifying: \[ \frac{x}{2} + 4 = 5x - 10 \] Multiply through by \(2\) to eliminate the fraction: \[ x + 8 = 10x - 20 \] Subtract \(x\) from both sides: \[ 8 = 9x - 20 \] Add \(20\) to both sides: \[ 28 = 9x \] Divide by \(9\): \[ x = \frac{28}{9} \]
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Equation: \(6x - 10 = 50\)
Simplifying: \[ 6x = 60 \] Divide by \(6\): \[ x = 10 \]
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Equation: \(\frac{5x}{9}=3\)
Simplifying: \[ 5x = 27 \] Divide by \(5\): \[ x = \frac{27}{5} \]
Summary of Solutions:
- First Equation: \(x = 10\)
- Second Equation: \(x = \frac{28}{9}\)
- Third Equation: \(x = 10\)
- Fourth Equation: \(x = \frac{27}{5}\)
Conclusion:
The equations that have the same solution are:
2(5x+4)=8x+28 has the same solution as 6x - 10 = 50.
So the final answer is:
2(5x+4)=8x+28 has the same solution as 6x - 10 = 50.