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What is the simplest form of 25^1/2?(1 point) Responses √25 Start Root 25 End Root 1/2√25 root index Start Fraction 1 over 2 En...Question
What is the simplest form of 2512
?(1 point)
Responses
25−−√
Start Root 25 End Root
25−−√12
root index Start Fraction 1 over 2 End Fraction Start Root 25 End Root
12.5
12.5
5
?(1 point)
Responses
25−−√
Start Root 25 End Root
25−−√12
root index Start Fraction 1 over 2 End Fraction Start Root 25 End Root
12.5
12.5
5
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Answered by
GPT-4o mini
To simplify the expression \( 2512 \), it seems to be a typographical error. If you meant to simplify \(\sqrt{2512}\), we can factor it:
1. First, we find the prime factorization of \( 2512 \):
- \( 2512 = 2 \times 1256 \)
- \( 1256 = 2 \times 628 \)
- \( 628 = 2 \times 314 \)
- \( 314 = 2 \times 157 \)
- \( 157 \) is a prime number.
So, the prime factorization is \( 2512 = 2^3 \times 157 \).
2. Now, we rewrite \(\sqrt{2512}\):
\[
\sqrt{2512} = \sqrt{2^3 \times 157} = \sqrt{2^2 \times 2 \times 157} = \sqrt{2^2} \times \sqrt{2 \times 157} = 2 \sqrt{2 \times 157} = 2 \sqrt{314}
\]
Thus, the simplest form of \(\sqrt{2512}\) is \( 2\sqrt{314} \).
If you meant something else by "2512", please clarify!
1. First, we find the prime factorization of \( 2512 \):
- \( 2512 = 2 \times 1256 \)
- \( 1256 = 2 \times 628 \)
- \( 628 = 2 \times 314 \)
- \( 314 = 2 \times 157 \)
- \( 157 \) is a prime number.
So, the prime factorization is \( 2512 = 2^3 \times 157 \).
2. Now, we rewrite \(\sqrt{2512}\):
\[
\sqrt{2512} = \sqrt{2^3 \times 157} = \sqrt{2^2 \times 2 \times 157} = \sqrt{2^2} \times \sqrt{2 \times 157} = 2 \sqrt{2 \times 157} = 2 \sqrt{314}
\]
Thus, the simplest form of \(\sqrt{2512}\) is \( 2\sqrt{314} \).
If you meant something else by "2512", please clarify!
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