2SO2+ O2 + 2H2O >>> 2H2SO4
320 gram SO2=5 moles check that
32 g O2= one mole
So looking at the balanced equation, you have an excess of SO2, or a deficit of O2.
320g of sulfur dioxide react with 32.0g of oxygen and excess water to form sulfuric acid (H2SO4)
a. What is the limiting reagent?
b. What is the theoretical yield of product?
c. How many grams of excess reagent will remain?
1 answer