Question

Using trial and error, if the area is 96 m^2, then the length and width are

Answer 1

To find the length and width of a rectangle where the area is 96 m² using trial and error, we can start with pairs of numbers that, when multiplied together, equal 96.

The area \( A \) of a rectangle is given by:

\[
A = \text{length} \times \text{width}
\]

We are looking for pairs of numbers \( (l, w) \) such that:

\[
l \times w = 96
\]

Let's try some pairs of factors of 96:

1. \( 1 \times 96 = 96 \) (Length: 96 m, Width: 1 m)
2. \( 2 \times 48 = 96 \) (Length: 48 m, Width: 2 m)
3. \( 3 \times 32 = 96 \) (Length: 32 m, Width: 3 m)
4. \( 4 \times 24 = 96 \) (Length: 24 m, Width: 4 m)
5. \( 6 \times 16 = 96 \) (Length: 16 m, Width: 6 m)
6. \( 8 \times 12 = 96 \) (Length: 12 m, Width: 8 m)

From this list, the pairs that give an area of 96 m² are:

- (1, 96)
- (2, 48)
- (3, 32)
- (4, 24)
- (6, 16)
- (8, 12)

You can choose any of these pairs based on the desired dimensions or your specific requirements.