What is the solution set of x+2≥6x+2≥6 and 3x≥63x≥6 ?(1 point) {x|xx|x}

Answer 1

To solve the inequalities you've provided, let's break them down step by step.

First Inequality: $x+2\ge 6$

1. Subtract 2 from both sides: $$x\ge 4$$

Second Inequality: $3x\ge 6$

1. Divide both sides by 3: $$x\ge 2$$

Combining the Solutions

Now, we need to combine the solution sets from the two inequalities.

• From the first inequality, the solution set is $x\ge 4$.
• From the second inequality, the solution set is $x\ge 2$.

The overall solution set must satisfy both inequalities. The more restrictive solution is $x\ge 4$.

Final Solution Set

The solution set is: $$x\mid x\ge 4$$

This indicates that $x$ can take any value equal to or greater than 4.

Answer 2

x+2>=6 and 3x>= 6

Answer 3

Let's solve each inequality step by step.

First Inequality: $x+2\ge 6$

1. Subtract $2$ from both sides: $$x\ge 6-2$$ $$x\ge 4$$

Second Inequality: $3x\ge 6$

1. Divide both sides by $3$: $$x\ge \frac{6}{3}$$ $$x\ge 2$$

Combined Solution

Now we combine the solutions from both inequalities:

• From the first inequality: $x\ge 4$
• From the second inequality: $x\ge 2$

Since $x$ must satisfy both conditions, we take the more restrictive condition:

$$x\ge 4$$

Final Solution Set

The solution set is: $$x\mid x\ge 4$$

This means $x$ can be any value that is 4 or greater.

Answer 4

What is the solution set of x+2>=6 and 3x>= 6

Answer 5

Let's solve the inequalities step by step:

Inequality 1: $x+2\ge 6$

1. Subtract $2$ from both sides: $$x\ge 6-2$$ $$x\ge 4$$

Inequality 2: $3x\ge 6$

1. Divide both sides by $3$: $$x\ge \frac{6}{3}$$ $$x\ge 2$$

Combined Solution

Now we need to find the solution set that satisfies both inequalities.

• From the first inequality: $x\ge 4$
• From the second inequality: $x\ge 2$

The more restrictive condition is $x\ge 4$. Therefore, we combine the two inequalities by taking the intersection of the solution sets:

Final Solution Set

The solution set is: $$x\mid x\ge 4$$

This means $x$ can take any value that is 4 or greater.

Answer 6

wrong

Answer 7

I apologize for any confusion in my previous responses. Let’s carefully solve the inequalities $x+2\ge 6$ and $3x\ge 6$ step by step.

Inequality 1: $x+2\ge 6$

To solve for $x$:

1. Subtract $2$ from both sides: $$x\ge 6-2$$ $$x\ge 4$$

Inequality 2: $3x\ge 6$

To solve for $x$:

1. Divide both sides by $3$: $$x\ge \frac{6}{3}$$ $$x\ge 2$$

Combined Solution

Now we consider both inequalities:

1. From the first inequality: $x\ge 4$
2. From the second inequality: $x\ge 2$

To satisfy both inequalities simultaneously, we take the more restrictive condition, which is $x\ge 4$.

Conclusion

The final solution set is: $$x\mid x\ge 4$$

This indicates that $x$ can take any value that is 4 or greater.

If you meant to combine these inequalities in a different way or there is any other clarification needed, please let me know!