Question

what is the value of x when f (x)=6

Answer 1

use the function to answer the question

f (x) = 1/2x + 3

what is the value of x when f(x)=6

Answer 2

what is the equation of a line that is parallel to y=-4x-3 and shifted down 3 units?

Answer 3

multiply (x-8) (x + 8)

Answer 4

To find the value of \( x \) when \( f(x) = 6 \), you need to know the expression or function for \( f(x) \). Could you provide the details of the function \( f(x) \)?

Answer 5

To find the value of \( x \) when \( f(x) = 6 \) using the function \( f(x) = \frac{1}{2}x + 3 \), we can set the equation to 6:

\[
\frac{1}{2}x + 3 = 6
\]

Now, let's solve for \( x \):

1. Subtract 3 from both sides:
\[
\frac{1}{2}x = 6 - 3
\]
\[
\frac{1}{2}x = 3
\]

2. Multiply both sides by 2 to isolate \( x \):
\[
x = 3 \times 2
\]
\[
x = 6
\]

So, the value of \( x \) when \( f(x) = 6 \) is \( \boxed{6} \).

Answer 6

To find the equation of a line that is parallel to the line given by \( y = -4x - 3 \) and shifted down 3 units, you need to follow these steps:

1. **Identify the slope**: The slope of the given line \( y = -4x - 3 \) is \(-4\). Since parallel lines have the same slope, the slope of the new line will also be \(-4\).

2. **Write the new line's equation**: Start with the slope-intercept form of the equation of a line, which is \( y = mx + b \), where \( m \) is the slope and \( b \) is the y-intercept.

3. **Shift down 3 units**: The original line has a y-intercept of \(-3\). If we shift down 3 units, we subtract 3 from the y-intercept:
\[
-3 - 3 = -6
\]

4. **Assemble the new equation**: Now, using the same slope and the new y-intercept:
\[
y = -4x - 6
\]

Therefore, the equation of the line that is parallel to \( y = -4x - 3 \) and shifted down 3 units is:
\[
\boxed{y = -4x - 6}
\]

Answer 7

To multiply the expressions \( (x - 8)(x + 8) \), you can use the difference of squares formula, which states that:

\[
(a - b)(a + b) = a^2 - b^2
\]

In this case, \( a = x \) and \( b = 8 \). Therefore, we have:

\[
(x - 8)(x + 8) = x^2 - 8^2
\]

Calculating \( 8^2 \):

\[
8^2 = 64
\]

So the expression becomes:

\[
x^2 - 64
\]

Thus, the result of multiplying \( (x - 8)(x + 8) \) is:

\[
\boxed{x^2 - 64}
\]