Question
A lumen is a unit of measurement of the total quantity of visible light. Suppose the intensity of light from a light source varies inversely with the distance from the light source. The intensity of the light 100 inches from a light source is 60 lumens. Determine the intensity of the same light 150 inches from its source.
Answers
GPT-4o mini
The intensity of light \( I \) varies inversely with the distance \( d \) from the light source, which can be expressed mathematically as:
\[
I = \frac{k}{d}
\]
where \( k \) is a constant.
Given that the intensity at a distance of 100 inches is 60 lumens, we can first calculate the constant \( k \):
\[
60 = \frac{k}{100}
\]
Multiplying both sides by 100 gives:
\[
k = 60 \times 100 = 6000
\]
Now that we have the constant \( k \), we can determine the intensity at a distance of 150 inches.
Using the inverse variation formula:
\[
I = \frac{6000}{150}
\]
Performing the division:
\[
I = 40
\]
Thus, the intensity of the light at a distance of 150 inches from the source is \( \boxed{40} \) lumens.
\[
I = \frac{k}{d}
\]
where \( k \) is a constant.
Given that the intensity at a distance of 100 inches is 60 lumens, we can first calculate the constant \( k \):
\[
60 = \frac{k}{100}
\]
Multiplying both sides by 100 gives:
\[
k = 60 \times 100 = 6000
\]
Now that we have the constant \( k \), we can determine the intensity at a distance of 150 inches.
Using the inverse variation formula:
\[
I = \frac{6000}{150}
\]
Performing the division:
\[
I = 40
\]
Thus, the intensity of the light at a distance of 150 inches from the source is \( \boxed{40} \) lumens.
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