To determine which equations have the same solution, we need to solve each equation for \( x \).
Equation A: \( \frac{x}{2} + 4 = 5x - 10 \)
- Multiply through by 2 to eliminate the fraction: \[ x + 8 = 10x - 20 \]
- Rearranging gives: \[ 8 + 20 = 10x - x \] \[ 28 = 9x \]
- Solving for \( x \): \[ x = \frac{28}{9} \]
Equation B: \( \frac{5x}{9} = 3 \)
- Multiply through by 9 to eliminate the fraction: \[ 5x = 27 \]
- Solving for \( x \): \[ x = \frac{27}{5} \]
Equation C: \( 6x - 10 = 50 \)
- Add 10 to both sides: \[ 6x = 60 \]
- Solving for \( x \): \[ x = 10 \]
Equation D: \( 2(5x + 4) = 8x + 28 \)
- Distribute the 2: \[ 10x + 8 = 8x + 28 \]
- Rearranging gives: \[ 10x - 8x = 28 - 8 \] \[ 2x = 20 \]
- Solving for \( x \): \[ x = 10 \]
Comparing Solutions:
- Equation A: \( x = \frac{28}{9} \)
- Equation B: \( x = \frac{27}{5} \)
- Equation C: \( x = 10 \)
- Equation D: \( x = 10 \)
Conclusion: Equations C and D have the same solution.
So, the correct matches are: _______ has the same solution as ________. C) 6x - 10 = 50 has the same solution as D) 2(5x + 4) = 8x + 28.