Add the polynomial expressions 2r^2−3r+4

Question

and −2r^2+3r+6
.(1 point)

Answer 1

To add the polynomial expressions \( 2r^2 - 3r + 4 \) and \( -2r^2 + 3r + 6 \), combine like terms:

1. Add the \( r^2 \) terms: \[ 2r^2 + (-2r^2) = 0r^2 \]

2. Add the \( r \) terms: \[ -3r + 3r = 0r \]

3. Add the constant terms: \[ 4 + 6 = 10 \]

Putting it all together, we get:

\[ 0r^2 + 0r + 10 = 10 \]

Thus, the sum of the polynomial expressions \( 2r^2 - 3r + 4 \) and \( -2r^2 + 3r + 6 \) is:

\[ \boxed{10} \]