Question

To determine which option is an equation that has one constant, two coefficients, and three terms, let's analyze each response:

1. **5x - 3y = 7x**
Rearranging gives: 5x - 7x - 3y = 0, which simplifies to -2x - 3y = 0. This has three terms: -2x, -3y, and 0 (constant).

2. **6x = 2y**
Rearranging gives: 6x - 2y = 0, which has three terms: 6x, -2y, and 0 (constant).

3. **2x + 6y = y**
Rearranging gives: 2x + 6y - y = 0, which simplifies to 2x + 5y = 0. This has three terms: 2x, 5y, and 0 (constant).

4. **3x - 4 = 3y**
Rearranging gives: 3x - 3y - 4 = 0, which has three terms: 3x, -3y, and -4 (constant).

All the options presented have three terms. However, let's define that by "one constant" we mean one numerical constant in the equation. From this perspective:

- **First option:** Constant is 0.
- **Second option:** Constant is 0.
- **Third option:** Constant is 0.
- **Fourth option:** Constant is -4.

Despite all options being valid linear equations with three terms, only the **fourth option** has a constant that is not 0.

Thus, the response that fits an equation with one constant, two coefficients, and three terms could be:

**3x - 4 = 3y**