Question
subtract 8 - 6 2/3
What is the difference in the simplest form
A 1/3
B 1 1/3
C 1 2/3
D 2 1/3
E 2 2/3
What is the difference in the simplest form
A 1/3
B 1 1/3
C 1 2/3
D 2 1/3
E 2 2/3
Answers
GPT-4o mini
To subtract \( 8 - 6 \frac{2}{3} \), we first convert \( 8 \) into a fraction:
\[
8 = \frac{8 \times 3}{3} = \frac{24}{3}
\]
Now we can rewrite the problem:
\[
8 - 6 \frac{2}{3} = \frac{24}{3} - \frac{20}{3}
\]
Next, convert \( 6 \frac{2}{3} \) into an improper fraction:
\[
6 \frac{2}{3} = 6 + \frac{2}{3} = \frac{18}{3} + \frac{2}{3} = \frac{20}{3}
\]
Now we perform the subtraction:
\[
\frac{24}{3} - \frac{20}{3} = \frac{24 - 20}{3} = \frac{4}{3}
\]
To convert \( \frac{4}{3} \) into a mixed number, we divide \( 4 \) by \( 3 \):
\[
4 \div 3 = 1 \quad \text{remainder } 1
\]
Thus,
\[
\frac{4}{3} = 1 \frac{1}{3}
\]
The difference in its simplest form is \( 1 \frac{1}{3} \).
The answer is **B. \( 1 \frac{1}{3} \)**.
\[
8 = \frac{8 \times 3}{3} = \frac{24}{3}
\]
Now we can rewrite the problem:
\[
8 - 6 \frac{2}{3} = \frac{24}{3} - \frac{20}{3}
\]
Next, convert \( 6 \frac{2}{3} \) into an improper fraction:
\[
6 \frac{2}{3} = 6 + \frac{2}{3} = \frac{18}{3} + \frac{2}{3} = \frac{20}{3}
\]
Now we perform the subtraction:
\[
\frac{24}{3} - \frac{20}{3} = \frac{24 - 20}{3} = \frac{4}{3}
\]
To convert \( \frac{4}{3} \) into a mixed number, we divide \( 4 \) by \( 3 \):
\[
4 \div 3 = 1 \quad \text{remainder } 1
\]
Thus,
\[
\frac{4}{3} = 1 \frac{1}{3}
\]
The difference in its simplest form is \( 1 \frac{1}{3} \).
The answer is **B. \( 1 \frac{1}{3} \)**.