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To solve the system of equations using the substitution method, we have the two equations:
1. \( y = -3 \)
2. \( y = 2x + 1 \)
Since the first equation gives us a direct value for \( y \), we can substitute that value into the second equation.
Substituting \( y = -3 \) into the second equation:
\[
-3 = 2x + 1
\]
Next, we solve for \( x \):
1. Subtract 1 from both sides:
\[
-3 - 1 = 2x
\]
\[
-4 = 2x
\]
2. Divide both sides by 2:
\[
x = -2
\]
Now we have the solution for \( x \). To find the value of \( y \), we can substitute \( x = -2 \) back into the first equation (though we already know what \( y \) is):
\[
y = -3
\]
Thus, the solution to the system of equations is:
\[
(x, y) = (-2, -3)
\]
So the final answer is:
\[
\boxed{(-2, -3)}
\]