Use the substitution method to solve the system y = -3, y = 2x + 1. (1 point)

To solve the system of equations using the substitution method, we have the two equations:

1. \( y = -3 \)
2. \( y = 2x + 1 \)

Since the first equation gives us a direct value for \( y \), we can substitute that value into the second equation.

Substituting \( y = -3 \) into the second equation:

\[
-3 = 2x + 1
\]

Next, we solve for \( x \):

1. Subtract 1 from both sides:

\[
-3 - 1 = 2x
\]
\[
-4 = 2x
\]

2. Divide both sides by 2:

\[
x = -2
\]

Now we have the solution for \( x \). To find the value of \( y \), we can substitute \( x = -2 \) back into the first equation (though we already know what \( y \) is):

\[
y = -3
\]

Thus, the solution to the system of equations is:

\[
(x, y) = (-2, -3)
\]

So the final answer is:

\[
\boxed{(-2, -3)}
\]