To solve the equation
\[ \frac{1}{4} (8 - 16g) + 8 = g, \]
let's follow these steps using the properties of equality.
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Distribute \(\frac{1}{4}\):
\[ \frac{1}{4} \times 8 - \frac{1}{4} \times 16g + 8 = g \]
This simplifies to:
\[ 2 - 4g + 8 = g \]
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Combine like terms:
\[ 10 - 4g = g \]
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Add \(4g\) to both sides:
\[ 10 = g + 4g \]
This simplifies to:
\[ 10 = 5g \]
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Divide both sides by 5:
\[ g = \frac{10}{5} \]
Simplifying gives:
\[ g = 2 \]
Now let's verify the solution by substituting \(g = 2\) back into the original equation.
Substituting \(g = 2\):
\[ \frac{1}{4} (8 - 16 \times 2) + 8 = 2 \]
Calculating inside the parentheses first:
\[ \frac{1}{4} (8 - 32) + 8 = 2 \] \[ \frac{1}{4} (-24) + 8 = 2 \] \[ -6 + 8 = 2 \] \[ 2 = 2 \]
Since both sides are equal, the solution is verified.
Thus, the solution to the equation is
\[ g = 2. \]