Question

Remember to use KEEP, CHANGE, FLIP to divide the fractions.%0D%0A%0D%0A%0D%0ASimplify if necessary.%0D%0A%0D%0A%0D%0AA.%0D%0AJulio (-6/3)%0D%0A%0D%0AB.%0D%0AWillow (-6)

Answer 1

To divide fractions using the KEEP, CHANGE, FLIP method, follow these steps:

1. **KEEP** the first fraction as it is.
2. **CHANGE** the division sign (÷) to a multiplication sign (×).
3. **FLIP** the second fraction (take the reciprocal of the second fraction).

From the information provided, it looks like there are only two isolated numbers, but let's set up a hypothetical division of the two fractions based on what you've given:

A. If we consider the first part as a fraction for Julio:
Julio: \(-\frac{6}{3}\)
This can be simplified:
\[
-\frac{6}{3} = -2
\]

B. For Willow, if she has a value of -6:
Willow: -6
This can be represented as a fraction \(-\frac{6}{1}\).

If you were to divide the two values (using \(-\frac{6}{3}\) divided by \(-6\)), you would use the KEEP, CHANGE, FLIP method as follows:

\[
-\frac{6}{3} \div -6 = -\frac{6}{3} \times -\frac{1}{6}
\]

Now, applying the KEEP, CHANGE, FLIP:

1. KEEP: \(-\frac{6}{3}\)
2. CHANGE: from division to multiplication (×)
3. FLIP: \(-6\) becomes \(-\frac{1}{6}\)

This gives:

\[
-\frac{6}{3} \times -\frac{1}{6}
\]

Now multiply:

\[
\frac{6 \times 1}{3 \times 6} = \frac{6}{18}
\]

This simplifies to:

\[
\frac{1}{3}
\]

So the final result of dividing \(-\frac{6}{3}\) by \(-6\) is \(\frac{1}{3}\).

Please verify if this aligns with the operations you intended; if you meant something different or specific, let me know!