Question

It takes 1 molecule of nitrogen and 3 molecules of hydrogen to produce 2 molecules of ammonia using the following formula: 1N2+ 3H2 → 2NH3 Identify which combination of molecules will produce ammonia with no leftovers? (1 point) Responses 8N2 and 4H2 8 n sub 2 and 4 h sub 2 5N2 and 6H2 5 n sub 2 and 6 h sub 2 4N2 and 4H2 4 n sub 2 and 4 h sub 2 2N2 and 6H2

Answer 1

To determine which combination of molecules will produce ammonia with no leftovers, we can analyze each option based on the given reaction:

The reaction is: \[ 1 \text{N}_2 + 3 \text{H}_2 \rightarrow 2 \text{NH}_3 \]

From the equation, we see that:

• 1 molecule of N2 reacts with 3 molecules of H2 to produce 2 molecules of NH3.

Now let's check each option:

1. 8 N2 and 4 H2:

   • For 8 N2, we need \( 8 \times 3 = 24 \) H2
   • We have only 4 H2, so this won't work.

2. 5 N2 and 6 H2:

   • For 5 N2, we need \( 5 \times 3 = 15 \) H2
   • We have only 6 H2, so this won't work.

3. 4 N2 and 4 H2:

   • For 4 N2, we need \( 4 \times 3 = 12 \) H2
   • We have only 4 H2, so this won't work.

4. 2 N2 and 6 H2:

   • For 2 N2, we need \( 2 \times 3 = 6 \) H2
   • We have 6 H2 available, which means:
     • 2 N2 will use 6 H2 perfectly.
     • This will produce \( 2 \times 2 = 4 \) NH3 molecules.
   • This option works perfectly with no leftovers.

The correct combination of molecules that will produce ammonia with no leftovers is 2 N2 and 6 H2.