Question

Order from least to greatest. 3 7/8, 3 1/5, 9/3

Answer 1

To order the numbers \(3 \frac{7}{8}\), \(3 \frac{1}{5}\), and \(\frac{9}{3}\) from least to greatest, we should first convert them all to improper fractions or decimals for easier comparison.

1. **Convert \(3 \frac{7}{8}\)**:
\[
3 \frac{7}{8} = \frac{3 \times 8 + 7}{8} = \frac{24 + 7}{8} = \frac{31}{8}
\]

2. **Convert \(3 \frac{1}{5}\)**:
\[
3 \frac{1}{5} = \frac{3 \times 5 + 1}{5} = \frac{15 + 1}{5} = \frac{16}{5}
\]

3. **Convert \(\frac{9}{3}\)**:
\[
\frac{9}{3} = 3
\]

Now we have:
- \(3 \frac{7}{8} = \frac{31}{8}\)
- \(3 \frac{1}{5} = \frac{16}{5}\)
- \(\frac{9}{3} = 3\)

Next, we convert \(\frac{16}{5}\) and \(\frac{31}{8}\) to decimals to compare more easily.

1. **Convert \(\frac{16}{5}\)**:
\[
\frac{16}{5} = 3.2
\]

2. **Convert \(\frac{31}{8}\)**:
\[
\frac{31}{8} = 3.875
\]

Now we can compare:
- \(3.2\) (which is \(3 \frac{1}{5}\))
- \(3\) (which is \(3\))
- \(3.875\) (which is \(3 \frac{7}{8}\))

Now putting these numbers in order from least to greatest:
- \(3\) (or \(\frac{9}{3}\))
- \(3 \frac{1}{5}\) (or \(3.2\))
- \(3 \frac{7}{8}\) (or \(3.875\))

Thus, the final order is:
\[
\frac{9}{3}, \quad 3 \frac{1}{5}, \quad 3 \frac{7}{8}
\]

Or, in mixed number form:
\[
3, \quad 3 \frac{1}{5}, \quad 3 \frac{7}{8}
\]