To convert the equation \(3x + 4y = 8\) into slope-intercept form, which is \(y = mx + b\) (where \(m\) is the slope and \(b\) is the y-intercept), we need to solve for \(y\).
Starting with the original equation:
\[ 3x + 4y = 8 \]
Subtract \(3x\) from both sides:
\[ 4y = -3x + 8 \]
Now, divide each term by \(4\):
\[ y = -\frac{3}{4}x + 2 \]
Thus, the slope-intercept form of the equation is:
\[ y = -\frac{3}{4}x + 2 \]
Here, the slope \(m\) is \(-\frac{3}{4}\) and the y-intercept \(b\) is \(2\).
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