Add the polynomial expressions 2r^2 - 3r +4 and -2r*2 + 3r + 6

Answer 1

To add the polynomial expressions \(2r^2 - 3r + 4\) and \(-2r^2 + 3r + 6\), you combine like terms:

1. Identify like terms:

   • \(2r^2\) and \(-2r^2\)
   • \(-3r\) and \(3r\)
   • \(4\) and \(6\)

2. Add the coefficients of like terms:

   • For \(r^2\): \(2r^2 + (-2r^2) = 0r^2\)
   • For \(r\): \(-3r + 3r = 0r\)
   • For the constant terms: \(4 + 6 = 10\)

3. Combine all the results:

   • \(0r^2 + 0r + 10 = 10\)

Thus, the sum of the polynomials \(2r^2 - 3r + 4\) and \(-2r^2 + 3r + 6\) is:

\[ 10 \]