Using the graph, derive the equation of the line in slope-intercept form (0,2) (1,-1

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To find the equation of the line in slope-intercept form (y = mx + b), we need to determine the slope (m) and the y-intercept (b) using the two points provided: (0, 2) and (1, -1).

  1. Calculate the slope (m): The formula for slope \( m \) between two points \((x_1, y_1)\) and \((x_2, y_2)\) is:

    \[ m = \frac{y_2 - y_1}{x_2 - x_1} \]

    Here, \((x_1, y_1) = (0, 2)\) and \((x_2, y_2) = (1, -1)\).

    \[ m = \frac{-1 - 2}{1 - 0} = \frac{-3}{1} = -3 \]

  2. Use one point to find the y-intercept (b): We can use the point (0, 2), the y-intercept is simply \( b = 2 \).

  3. Write the equation: Now that we have \( m \) and \( b \), we can write the equation of the line:

    \[ y = -3x + 2 \]

Thus, the equation of the line in slope-intercept form is \( y = -3x + 2 \).

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