To solve the equation \( 27^{x \frac{3}{4}} - 1 = 26 \), we first simplify it:
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Isolate the term with the exponent: \[ 27^{x \frac{3}{4}} = 26 + 1 = 27 \]
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Since \( 27 \) can be expressed as \( 3^3 \), we can also express it as: \[ 27^{x \frac{3}{4}} = (3^3)^{x \frac{3}{4}} = 3^{3x \frac{3}{4}} = 3^3 \]
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This implies: \[ 3x \frac{3}{4} = 3 \]
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Divide both sides by 3: \[ x \frac{3}{4} = 1 \]
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Multiply both sides by \( \frac{4}{3} \): \[ x = \frac{4}{3} \]
None of the provided options correspond to \( \frac{4}{3} \), suggesting an error in the assumptions or the options provided. Let's check if we made any calculation errors.
Since \( 27^{x \frac{3}{4}} = 27 \) directly implies \( x \frac{3}{4} = 1 \) indeed gives \( x = \frac{4}{3} \).
Assuming that the options provided might represent a misunderstanding of the fractions, the only fraction approaching a solution from \( 0, \frac{25}{27}, 3, 1 \) doesn’t apply.
Therefore, the answer to \( 27^{x \frac{3}{4}} = 27 \) leads us clearly to \( x = \frac{4}{3} \), which is unfortunately not one of the provided options.
Please verify the question for correctness or option listings. However, based on the direct calculation:
The correct value for \(x\) based on solving is \( \frac{4}{3} \).