To determine which points are part of the solution set for the inequality \(y \leq 25x + 1\), we need to check each point by substituting the \(x\) value into the inequality and comparing the \(y\) value.
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For the point \((-10, 6)\): \[ y \leq 25(-10) + 1 \Rightarrow 6 \leq -250 + 1 \Rightarrow 6 \leq -249 \quad \text{(False)} \]
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For the point \((10, 6)\): \[ y \leq 25(10) + 1 \Rightarrow 6 \leq 250 + 1 \Rightarrow 6 \leq 251 \quad \text{(True)} \]
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For the point \((10, 5.5)\): \[ y \leq 25(10) + 1 \Rightarrow 5.5 \leq 250 + 1 \Rightarrow 5.5 \leq 251 \quad \text{(True)} \]
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For the point \((10, 4)\): \[ y \leq 25(10) + 1 \Rightarrow 4 \leq 250 + 1 \Rightarrow 4 \leq 251 \quad \text{(True)} \]
Therefore, the points \((10, 6)\), \((10, 5.5)\), and \((10, 4)\) are all part of the solution set for the inequality \(y \leq 25x + 1\).
The correct answer(s) are:
- \((10, 6)\)
- \((10, 5.5)\)
- \((10, 4)\)
All of these points are valid solutions, but if you're only looking for one, you can choose any of them.