Asked by Anonymous
An internal explosion breaks an object, initially at rest, into two pieces, one of which has 2 times the mass of the other. If 22500 J is released in the explosion, how much kinetic energy does each piece acquire?
Answers
Answered by
bobpursley
The lesser mass will have twice the velocity.
KE= 1/2mv^2 +1/2 2M (v/2)^2=22500
1/2mv^2+ 1/4mv^2=
so the smaller piece has twice as much energy than the larger
so smaller has 2/3 22500 Joules
KE= 1/2mv^2 +1/2 2M (v/2)^2=22500
1/2mv^2+ 1/4mv^2=
so the smaller piece has twice as much energy than the larger
so smaller has 2/3 22500 Joules
Answered by
drwls
It is not necessary that all of the energy of the explosion be converted to kinetic energy of the two pieces. There will usually also be heating of the pieces, and the release of gas.
IF 22500 J is released in the explosion as kinetic energy of the only two pieces, then the approach of BobPursley will yield the answer.
IF 22500 J is released in the explosion as kinetic energy of the only two pieces, then the approach of BobPursley will yield the answer.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.