Question

What is the decimal form of the following binary IP address? 11001101.00111001.10101001.01000010

Answer 1

To convert the binary IP address `11001101.00111001.10101001.01000010` into decimal form, we need to convert each 8-bit octet from binary to decimal.

1. **Convert the first octet: 11001101**
- \( 1 \times 2^7 = 128 \)
- \( 1 \times 2^6 = 64 \)
- \( 0 \times 2^5 = 0 \)
- \( 0 \times 2^4 = 0 \)
- \( 1 \times 2^3 = 8 \)
- \( 1 \times 2^2 = 4 \)
- \( 0 \times 2^1 = 0 \)
- \( 1 \times 2^0 = 1 \)
- Adding these values together: \( 128 + 64 + 0 + 0 + 8 + 4 + 0 + 1 = 205 \)

2. **Convert the second octet: 00111001**
- \( 0 \times 2^7 = 0 \)
- \( 0 \times 2^6 = 0 \)
- \( 1 \times 2^5 = 32 \)
- \( 1 \times 2^4 = 16 \)
- \( 1 \times 2^3 = 8 \)
- \( 0 \times 2^2 = 0 \)
- \( 0 \times 2^1 = 0 \)
- \( 1 \times 2^0 = 1 \)
- Adding these values together: \( 0 + 0 + 32 + 16 + 8 + 0 + 0 + 1 = 57 \)

3. **Convert the third octet: 10101001**
- \( 1 \times 2^7 = 128 \)
- \( 0 \times 2^6 = 0 \)
- \( 1 \times 2^5 = 32 \)
- \( 0 \times 2^4 = 0 \)
- \( 1 \times 2^3 = 8 \)
- \( 0 \times 2^2 = 0 \)
- \( 0 \times 2^1 = 0 \)
- \( 1 \times 2^0 = 1 \)
- Adding these values together: \( 128 + 0 + 32 + 0 + 8 + 0 + 0 + 1 = 169 \)

4. **Convert the fourth octet: 01000010**
- \( 0 \times 2^7 = 0 \)
- \( 1 \times 2^6 = 64 \)
- \( 0 \times 2^5 = 0 \)
- \( 0 \times 2^4 = 0 \)
- \( 0 \times 2^3 = 0 \)
- \( 1 \times 2^2 = 4 \)
- \( 0 \times 2^1 = 0 \)
- \( 0 \times 2^0 = 0 \)
- Adding these values together: \( 0 + 64 + 0 + 0 + 0 + 4 + 0 + 0 = 68 \)

Now, combining these decimal values, the decimal form of the IP address `11001101.00111001.10101001.01000010` is:

**205.57.169.68**