Question
Add the polynomial expressions negative 2 r squared plus 3 r plus 6 and -2r^2+3r+6
Answers
Answer
this is wrong
Answer
Make sure to pay attention to the positive and negative signs and add to 0 where necessary for any variables or values.
Answered by
GPT-4o mini
To add the polynomial expressions \(-2r^2 + 3r + 6\) and \(-2r^2 + 3r + 6\), you combine like terms.
The expressions can be written as:
\[
(-2r^2 + 3r + 6) + (-2r^2 + 3r + 6)
\]
Now, we can add the coefficients of like terms:
1. Combine the \(r^2\) terms:
\(-2r^2 + (-2r^2) = -4r^2\)
2. Combine the \(r\) terms:
\(3r + 3r = 6r\)
3. Combine the constant terms:
\(6 + 6 = 12\)
Putting it all together, the result is:
\[
-4r^2 + 6r + 12
\]
Therefore, the sum of the two polynomial expressions is:
\[
-4r^2 + 6r + 12
\]
The expressions can be written as:
\[
(-2r^2 + 3r + 6) + (-2r^2 + 3r + 6)
\]
Now, we can add the coefficients of like terms:
1. Combine the \(r^2\) terms:
\(-2r^2 + (-2r^2) = -4r^2\)
2. Combine the \(r\) terms:
\(3r + 3r = 6r\)
3. Combine the constant terms:
\(6 + 6 = 12\)
Putting it all together, the result is:
\[
-4r^2 + 6r + 12
\]
Therefore, the sum of the two polynomial expressions is:
\[
-4r^2 + 6r + 12
\]
Answered by
GPT-4o mini
I apologize for any confusion; however, let's clarify and correctly combine the two polynomial expressions step by step.
The two polynomial expressions are:
1. \(-2r^2 + 3r + 6\)
2. \(-2r^2 + 3r + 6\)
When you add them together, you proceed as follows:
\[
(-2r^2 + 3r + 6) + (-2r^2 + 3r + 6)
\]
Now, combine like terms:
- For the \(r^2\) terms:
\[
-2r^2 + (-2r^2) = -4r^2
\]
- For the \(r\) terms:
\[
3r + 3r = 6r
\]
- For the constant terms:
\[
6 + 6 = 12
\]
Combining all these results gives us:
\[
-4r^2 + 6r + 12
\]
If this is not the desired calculation or if there is something specific you need to check, please let me know, and I will help clarify!
The two polynomial expressions are:
1. \(-2r^2 + 3r + 6\)
2. \(-2r^2 + 3r + 6\)
When you add them together, you proceed as follows:
\[
(-2r^2 + 3r + 6) + (-2r^2 + 3r + 6)
\]
Now, combine like terms:
- For the \(r^2\) terms:
\[
-2r^2 + (-2r^2) = -4r^2
\]
- For the \(r\) terms:
\[
3r + 3r = 6r
\]
- For the constant terms:
\[
6 + 6 = 12
\]
Combining all these results gives us:
\[
-4r^2 + 6r + 12
\]
If this is not the desired calculation or if there is something specific you need to check, please let me know, and I will help clarify!
Answered by
GPT-4o mini
Let me carefully go through the addition of the two polynomial expressions \(-2r^2 + 3r + 6\) and \(-2r^2 + 3r + 6\), ensuring that all positive and negative signs are accurately accounted for.
### Given Polynomials:
1. **First polynomial:** \(-2r^2 + 3r + 6\)
2. **Second polynomial:** \(-2r^2 + 3r + 6\)
### Adding the Polynomials:
We perform the addition as follows:
\[
(-2r^2 + 3r + 6) + (-2r^2 + 3r + 6)
\]
Now, let's combine like terms carefully:
1. **Combine \(r^2\) terms:**
\[
-2r^2 + (-2r^2) = -4r^2
\]
2. **Combine \(r\) terms:**
\[
3r + 3r = 6r
\]
3. **Combine constant terms:**
\[
6 + 6 = 12
\]
### Final Result:
Putting it all together, the result is:
\[
-4r^2 + 6r + 12
\]
### Conclusion:
The signs have been carefully observed, and each term has been combined correctly. All positive and negative signs were taken into account, and there are no terms that sum to zero in this case.
The final result remains:
\[
-4r^2 + 6r + 12
\]
If you need any additional clarification or adjustments, please let me know!
### Given Polynomials:
1. **First polynomial:** \(-2r^2 + 3r + 6\)
2. **Second polynomial:** \(-2r^2 + 3r + 6\)
### Adding the Polynomials:
We perform the addition as follows:
\[
(-2r^2 + 3r + 6) + (-2r^2 + 3r + 6)
\]
Now, let's combine like terms carefully:
1. **Combine \(r^2\) terms:**
\[
-2r^2 + (-2r^2) = -4r^2
\]
2. **Combine \(r\) terms:**
\[
3r + 3r = 6r
\]
3. **Combine constant terms:**
\[
6 + 6 = 12
\]
### Final Result:
Putting it all together, the result is:
\[
-4r^2 + 6r + 12
\]
### Conclusion:
The signs have been carefully observed, and each term has been combined correctly. All positive and negative signs were taken into account, and there are no terms that sum to zero in this case.
The final result remains:
\[
-4r^2 + 6r + 12
\]
If you need any additional clarification or adjustments, please let me know!