To compare the populations of Longview and Milltown, let's first express everything using a common base.
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Longview Population: \[ \text{Population of Longview} = 4^7 \]
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Springhill Population: \[ \text{Population of Springhill} = 4^{10} \]
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Milltown Population: Milltown's population is \( 4^{-2} \) of Springhill's population, which we can calculate as: \[ \text{Population of Milltown} = 4^{-2} \times 4^{10} \] Using the property of exponents \( a^m \times a^n = a^{m+n} \): \[ \text{Population of Milltown} = 4^{-2 + 10} = 4^{8} \]
Now we need to compare the populations of Longview and Milltown:
- Longview: \( 4^7 \)
- Milltown: \( 4^8 \)
Since \( 4^8 \) (Milltown) is greater than \( 4^7 \) (Longview), we can conclude that:
\[ \text{Milltown's population is greater than Longview's population.} \]