If the perimeter of a rectangle is 60 ft and its length is 18 ft, find its width. (see formula in number 1)

Answer 1

To find the width of the rectangle, we can use the formula for the perimeter of a rectangle:

\[ P = 2L + 2W \]

where \( P \) is the perimeter, \( L \) is the length, and \( W \) is the width.

Given:

• \( P = 60 \) ft
• \( L = 18 \) ft

We can substitute these values into the formula:

\[ 60 = 2(18) + 2W \]

Calculating \( 2(18) \):

\[ 60 = 36 + 2W \]

Now, we will isolate \( 2W \):

\[ 60 - 36 = 2W \] \[ 24 = 2W \]

Now, divide both sides by 2 to solve for \( W \):

\[ W = \frac{24}{2} \] \[ W = 12 \]

So, the width of the rectangle is \( 12 \) ft.