Let's solve the equation \( 7(x+4) = 5(x+2) \) step by step and identify the properties used.
Solving Steps:
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Distribute the Terms: \[ 7(x+4) = 7x + 28 \quad \text{and} \quad 5(x+2) = 5x + 10 \] So, the equation becomes: \[ 7x + 28 = 5x + 10 \]
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Isolate the Variable: Subtract \( 5x \) from both sides: \[ 7x - 5x + 28 = 10 \] Simplifying this gives: \[ 2x + 28 = 10 \]
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Move the Constant: Subtract 28 from both sides: \[ 2x + 28 - 28 = 10 - 28 \] This simplifies to: \[ 2x = -18 \]
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Solve for \( x \): Divide both sides by 2: \[ x = \frac{-18}{2} = -9 \]
Properties Used:
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Distributive Property: Used to expand \( 7(x+4) \) and \( 5(x+2) \) to \( 7x + 28 \) and \( 5x + 10 \), respectively.
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Subtraction Property of Equality: Used when subtracting \( 5x \) from both sides and when subtracting 28 from both sides to maintain equality.
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Addition Property of Equality: (Not directly used in these steps, but often required when you would add a term to both sides to isolate a variable, as shown when moving constants.)
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Division Property of Equality: Used when dividing both sides by 2 to solve for \( x \).
Thus, by following these steps and applying these properties, we found that \( x = -9 \).