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Original Question
What exponent would make the two expressions equivalent: (33)x=324 ?(1 point) Responses 27 15 15 21 21 8Asked by Ame
What exponent would make the two expressions equivalent: (33)x=324 ?(1 point)
Responses
15
21
27
8
Responses
15
21
27
8
Answers
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Answered by
GPT-4o mini
To solve for the exponent \( x \) in the equation \( 33^x = 324 \), we can start by writing \( 324 \) as a power of \( 3 \).
First, let's factor \( 324 \):
\[
324 = 18 \times 18 = (3 \times 6) \times (3 \times 6) = (3 \times (2 \times 3)) \times (3 \times (2 \times 3))
\]
\[
= 3^4 \times 2^2
\]
However, for simplicity, we can express \( 324 \) as a power of \( 3 \):
\[
324 = 3^4 \times 2^2 \quad \text{(not useful, let's find a more straightforward power)}
\]
\( 324 = 18^2 = (3^2 \times 2)^2 = 3^4 \times 2^2 \).
Instead, let's use logarithms. Taking the logarithm of both sides of the equation:
\[
\log(33^x) = \log(324)
\]
Using the logarithmic property \( \log(a^b) = b\log(a) \):
\[
x \log(33) = \log(324)
\]
Now solving for \( x \):
\[
x = \frac{\log(324)}{\log(33)}
\]
Next, we evaluate the logs. You can use a calculator to find approximate values:
- \( \log(324) \approx 2.510 \)
- \( \log(33) \approx 1.519 \)
Now, calculating \( x \):
\[
x \approx \frac{2.510}{1.519} \approx 1.65
\]
Now compare with given options: \( 15, 21, 27, 8 \). None of these match.
It appears I made a mistake in determining the possible powers of \( 33 \). Let’s evaluate integers for potential matches.
To find an answer directly matching with your options, let’s try each exponent quickly:
- \( 33^8 \) is much greater than \( 324 \)
- \( 33^{15} \) is also far too large.
- \( 33^{21} \) much higher, and \( 33^{27} \) would be much too far.
Instead, we note that \( 324 \) is \( 18^2 \), and \( 33 \) itself doesn’t exactly fall into our checks, which leads to evaluating this accurately would involve roots or rational powers.
### Estimation
Equal estimations led me to utilize logarithmic simplifications, so guess \( x \) would be smaller than any integer provided.
If you check against reevaluating powers and logarithmically accurate \( x \):
**Final estimate based on checks \( x \to \text{closer estimated to } approximations \to 2 or less.**
None were \( 15, 21, 27, 8 \).
The problem implies further simplification may be an approach mismatch on integer-level simplifications, lean against approximating.
The apparent \( 27 \) most closely checks conditions against logarithmic approximations or computational errors.
None yields exact twice of values.
### Conclusion:
Focusing choices are misaligned; clarify suitable bases, and numerically check all iterations against logs for next space.
Would require real match checking logarithm tables or any trigonometrical closers as decimal semi-powers through base-offs.
First, let's factor \( 324 \):
\[
324 = 18 \times 18 = (3 \times 6) \times (3 \times 6) = (3 \times (2 \times 3)) \times (3 \times (2 \times 3))
\]
\[
= 3^4 \times 2^2
\]
However, for simplicity, we can express \( 324 \) as a power of \( 3 \):
\[
324 = 3^4 \times 2^2 \quad \text{(not useful, let's find a more straightforward power)}
\]
\( 324 = 18^2 = (3^2 \times 2)^2 = 3^4 \times 2^2 \).
Instead, let's use logarithms. Taking the logarithm of both sides of the equation:
\[
\log(33^x) = \log(324)
\]
Using the logarithmic property \( \log(a^b) = b\log(a) \):
\[
x \log(33) = \log(324)
\]
Now solving for \( x \):
\[
x = \frac{\log(324)}{\log(33)}
\]
Next, we evaluate the logs. You can use a calculator to find approximate values:
- \( \log(324) \approx 2.510 \)
- \( \log(33) \approx 1.519 \)
Now, calculating \( x \):
\[
x \approx \frac{2.510}{1.519} \approx 1.65
\]
Now compare with given options: \( 15, 21, 27, 8 \). None of these match.
It appears I made a mistake in determining the possible powers of \( 33 \). Let’s evaluate integers for potential matches.
To find an answer directly matching with your options, let’s try each exponent quickly:
- \( 33^8 \) is much greater than \( 324 \)
- \( 33^{15} \) is also far too large.
- \( 33^{21} \) much higher, and \( 33^{27} \) would be much too far.
Instead, we note that \( 324 \) is \( 18^2 \), and \( 33 \) itself doesn’t exactly fall into our checks, which leads to evaluating this accurately would involve roots or rational powers.
### Estimation
Equal estimations led me to utilize logarithmic simplifications, so guess \( x \) would be smaller than any integer provided.
If you check against reevaluating powers and logarithmically accurate \( x \):
**Final estimate based on checks \( x \to \text{closer estimated to } approximations \to 2 or less.**
None were \( 15, 21, 27, 8 \).
The problem implies further simplification may be an approach mismatch on integer-level simplifications, lean against approximating.
The apparent \( 27 \) most closely checks conditions against logarithmic approximations or computational errors.
None yields exact twice of values.
### Conclusion:
Focusing choices are misaligned; clarify suitable bases, and numerically check all iterations against logs for next space.
Would require real match checking logarithm tables or any trigonometrical closers as decimal semi-powers through base-offs.
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